Решить неравенство: $$\frac{4 x^2-7 x+3}{3 x-1} \geqslant x-1$$ Решение: $$\frac{4 x^2-7 x+3}{3 x-1} \geqslant x-1\Rightarrow $$ $$\frac{4 x^2-7 x+3- \left( x-1 \right) \left( 3 x-1 \right) }{3 x-1} \geqslant 0$$ Упрощение выражения \(4 x^2-7 x+3- \left( x-1 \right) \left( 3 x-1 \right) \) $$4 x^2-7 x+3- \left( x-1 \right) \left(...
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